Question

Calculate the moles of potassium sulfide formed when 5.4g of potassium gas reacts with excess sulfur.

2 K+S > K2S

Answer 1

Answer:-

$2 K+S \rightarrow K_2S$

$Moles \ of \ K = {given \ mass \over atomic \ mass}$

$Moles \ of \ K = { 5.4\over 39}$

$Moles \ of \ K = 0.13$

1 mole potassium gives 2 mole potassium sulphide

So 0.13 mole potassium will give 0.26 mole of potassium sulphide

Mass of potassium sulphide =moles × atomic mass

= 0.13×110.2

$=14.32 \ g\ answer$