Question

V1 = 0.55L, P1 = 740mmHg, V2 = 0.80 L, P2 =

Answer 1

Given:

$V_1 = 0.55L, P_1 = 740mmHg, V_2 = 0.80 L, P_2=?$

We know that in a system moles are constant then the ideal gas equation seem as

$\dfrac{P_1}{V_1}=\dfrac{P_2}{V_2}\\$

$\Rightarrow P_2= \dfrac{P_1\times V_1}{V_2}\\$

$\Rightarrow P_2=\dfrac{740\times 0.55}{0.80}\\$

$\Rightarrow P_2=508.75mmHg\\$