Answer to Question #185534 in General Chemistry for fred

Question

Hello, can you please provide the complete solutions of these questions. The answers are already given.

3. A sample of Al2(SO4)3 weighing 7.52-g was dissolved in enough water

and diluted to 250.0-mL. 100.0-mL of the dilution was transferred to

another flask, 10.0-mL of 0.050M EDTA, 20-mL of buffer solution, 50-mL of

alcohol and 2.0-mL dithizone TS were added. The resulting solution

required 8.7-mL of 0.031M ZnSO4 to reach the endpoint. (Note: Each mL

of 0.050M EDTA is equivalent to 16.66-mg Al2(SO4)3·18H20). Compute for

the percent purity of the sample.

Molar Mass: Al2(SO4)3·18H2O = 666.5

answer: 2.5% Al2(SO4)3

Answer 1

Molar Mass: $Al_2(SO_4)_3·18H_2O$ = 666.5

Percent purity of the sample.2.5% $Al_2(SO_4)_3$