Answer to Question #185532 in General Chemistry for FREDELYN

Question

Hello, can you please provide the complete solutions of these questions. The answers are already given.

1. The silver ion in a 25.00-mL sample was converted to dicyanoargentate

(l) ion by the addition of an excess solution containing Ni(CN) 4

-2:

Ni(CN)4

-2 + 2 Ag+1 2Ag(CN)2

-1 + Ni+2

The liberated nickel ion was titrated with 43.77-mL of 0.02408M EDTA.

Calculate the molar concentration of the silver solution.

Molar Masses: Ni = 58.69 Ag = 107.9

answer: 0.08432M Ag+1

Answer 1

Molar Masses: Ni = 58.69 Ag = 107.9

Molar concentration : 0.08432M $Ag^{+1}$