BaO (s) + H2O (g) = Ba(OH)2 (s) If you want to completely react 10.25 g of barium oxide, how many grams of water will you need?
From the equation, the ratio of barium Oxide and water is 1:1
Molar Mass of BaO = 153.33
10.25/153.33 = 0.0668 moles
Molar Mass of H2O = 18.015
= 0.0668 × 18.015
= 1.204g
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