Calculations show that a reaction should yield 5.67 g of carbon dioxide gas, CO2 what volume should be expected at 26 C and 782 mmHg
Mass of CO2 yielded = 5.67 g
Moles of CO2 = 5.6744=0.128 mol\dfrac{5.67}{44}=0.128\space mol445.67=0.128 mol
Pressure, P=782 mm of Hg=104.258 kPaP=782\space mm\space of \space Hg=104.258\space kPaP=782 mm of Hg=104.258 kPa
Temperature, T=26°C=299 KT=26\degree C=299\space KT=26°C=299 K
According to ideal gas law,
PV=nRTPV=nRTPV=nRT
V=nRTP=0.128×8.314×299104258V=\dfrac{nRT}{P}=\dfrac{0.128\times8.314\times299}{104258}V=PnRT=1042580.128×8.314×299
V=0.00305 m3=3.05 LV=0.00305\space m^3=3.05\space LV=0.00305 m3=3.05 L
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