Assume the given amount of RbF fully dissociates in water. Calculate the molarity of a solution if 138.42 g of RbF are dissolved into a solution of water that has a final volume of 2.00 L.
Molar mass of RbF = 104.47 g/mol
Mass of RbF = 138.42g
number of moles = 138.42/104.47 = 1.32 moles
Volume = 2.00 L
molarity = number of moles/ Volume = "\\dfrac{1.32}{2.00}" = 0.66 mol/L = 0.66 M
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