Question

74.00 mL of a concentrated ethanol solution is added to a container to make 1.63 L of a 0.18 M diluted solution. What was the initial concentration of the ethanol?

Answer 1

$M_1V_1=M_2V_2$

$M_1×74mL=1630mL×0.18M$

$M_1=\frac {1630mL×0.18M}{74mL}$

$M_1=3.965M$