Question

calculate and describe how to make 20ml of 0.06M HCL starting with 6.0M HCL and water.

Answer 1

Given C₁ = 6.0 M, C₂ = 0.06 M, and V₂ = 20 mL. The initial volume is unknown (V₁).

$C_1V_1=C_2V_2$

Therefore,

$V_1=\frac{C_2V_2}{C_1}=\frac{0.06M\times20mL}{6.0M}=0.2mL$

To make the required solution, 0.2 mL of the 6.0 M HCl should be carefully measured and transferred to a volumetric flask, and then diluted with distilled water to the 20 mL mark.