Question

6. According to the Arrhenius Theory, a product of any neutralization reaction is 

7. Aqueous sodium chloride contains 5.85g solute dissolved in 250mL solution M nacl = 5.85g/mol, calculate the concentration of the solution in mol/L

8. Water is added to 100ml of 0.15 mol/L sodium nitrate, NaNO3 (aq), to make 700ml of diluted solution. What is the molar concentration of the diluted solution

Answer 1

When Arrhenius acid and Arrhenius base reacts, salt and water is formed as product, the reaction is known as neutralization reaction.

Number of moles n= mass/molar mass

Molar mass of NaCl=58.5 g/mol

Mass = 5.85g

$Moles(n) = \frac{5.85}{58.5}=0.1moles$

Volume, V=250mL =0.25 L

∴

Morality = $\frac{0.1}{0.25} = 0.4mol/L$