Which of the following reactions is sulphuroxide acting as an oxidizing agent
2SO2+2H2O+O2- 2H3SO4
The correct equation is:
2SO2 + 2H2O + O2 --> 2H2SO4 (not H3SO4)
Sulphur (IV) oxide is not acting as an oxidizing agent in this reaction. S changes its oxidation state from +4 to +6, therefore, it acts as a reducing agent. Oxidizing agent is O2 in this case.
Comments
Leave a comment