Question

Propane, C3H8(g), and oxygen gas, O2(g), react to produce carbon dioxide, CO2(g), and water, H2O(g). If all gases are at 25.0oC and 102 kPa, what volume of carbon dioxide is produced when 5.44 g of propane reacts with excess oxygen?

a- 0.13 L

b- 1.05 L

c- 8.99 L

d- 65.6 L

Answer 1

balanced equation is

C3H8+5O2→3CO2+4H2O

1 moles of propane produces 3 moles of CO₂

Molar Mass of propane = 44.1

= 5.44/44.1 = 0.1234moles of propane

= 0.1234 × 3 = 0.3701moles of CO₂

Molar Mass of CO₂ = 44.01

= 44.01 × 0.3701

= 16.287g ofCO₂