Question

8.0 mL of 0.10 M HCl is titrated with 0.10 M NaOH. Perform the following calculations with all workout shown

pH of the acid before any NaOH is added

Volume of 0.10 M NaOH needed to reach the equivalence point

pH at the equivalence point

Answer 1

$PH=- log [H^+]$

$PH=-log[0.10]=1$

NaOH (aq) + HCl (aq) → NaCl (aq) + H₂O (l)

Volume of NaOH = 8.0 ml