Answer to Question #183181 in General Chemistry for dsad

Question

Titrant-->NaOH

Analyte--> HC2H3O2

Questions (answer all and please show workout!-->

Find pH at HALF-WAY point

Find Volume at HALF-WAY point

Find pH at EQUIVALENCE POINT

Find Volume at EQUIVALENCE POINT

DATA-->

Volume 0.10 M HC2H3O2 used (mL)-->8.00

Volume 0.10 M NaOH added (mL)

0.00

1.00

1.50

2.00

2.50

3.00

3.50

3.98

4.00

4.01

4.05

4.10

4.12

4.13

4.15

4.20

4.25

4.31

4.35

4.40

4.45

4.50

4.51

4.61

4.70

4.75

4.77

4.80

4.81

5.01

5.21

5.40

5.60

6.10

6.50

7.10

7.50

8.40

9.50

10.50

11.50

12.50

14.00

15.00

PH

2.55

3.60

3.87

4.09

4.47

4.94

5.57

6.43

6.69

6.89

7.17

7.45

7.73

8.35

9.25

9.51

9.81

9.94

10.15

10.23

10.33

10.43

10.49

10.57

10.64

10.73

10.80

10.85

10.90

11.18

11.31

11.41

11.53

11.83

11.94

12.10

12.21

12.33

12.46

12.50

12.63

12.69

12.79

12.84

Answer 1

The half equivalence point represents the point at which exactly half of the acid in the buffer solution has reacted with the titrant. The half equivalence point is relatively easy to determine because at the half equivalence point, the pKa of the acid is equal to the pH of the solution.

Equivalence point: point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution. At the equivalence point in an acid-base titration, moles of base = moles of acid and the solution only contains salt and water.