Question

1. What is the heat (q) needed by water with molar heat of vaporization of 36 kJ if it is 40.0 g in mass and boils at 105°C? Note that the molar mass of water is 18.0 g/mol.

Answer 1

$Moles = \frac{40}{18}=2.2 moles$

Heat of Vap$= 105×2.2×36=184.2kj$