A balloon has a volume of 6.5 L at a pressure of 0.98 atm. What is the volume of the balloon in liters if the atmospheric pressure is reduced to 0.36 atm?
Here we have , Two situations
Situation 1:
V1=6.5LV_1=6.5 LV1=6.5L
P1=0.98atmP_1=0.98 atmP1=0.98atm
Situation 2:
P2=0.36atmP_2=0.36 atmP2=0.36atm
V2=V2(Let)V_2=V_2(Let)V2=V2(Let)
Now we know that :
P1V1=P2V2P_1V_1=P_2V_2P1V1=P2V2
V2=P1V1P2V_2=\dfrac{P_1V_1}{P_2}V2=P2P1V1
V2=0.98×6.50.36=17.6944LV_2=\dfrac{0.98\times6.5}{0.36}=17.6944 LV2=0.360.98×6.5=17.6944L
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