Answer to Question #180691 in General Chemistry for Nieky

Question

what mass of Fe(OH) would be produced if 250 ML of 0.25 0M NaOH were added to solution containing excess FeCl3

Answer 1

Fe(OH)₂ + 2NaOH → Na₂[Fe(OH)₄] 

Ratio 1 : 2

Moles of NaOH = Volume × Molar Mass

0.25×39.997= 10moles

Moles of Fe(OH) = 10÷2 = 5 moles

Mass =5× 89.86= 434grams

Mass= 434g