Question

Ammonium chloride and calcium hydroxide react according to the following balanced equation:

2 NH₄Cl_(aq)  + Ca(OH)_2(aq)  -->  CaCl_2(aq)  + 2 NH_3(g)  + 2 H₂O_(l)

What mass in grams of Ca(OH)₂ is needed to make 1.46 L of a 0.78 M NH₃ solution?

Answer 1

Moles of NH₃ = $0.78 × 1.46=1.1388 moles$

Moles of Ca(OH)₂$=\frac{1.1388}{2}=0.5694$

Grams of Ca(OH)₂$= 0.5694×74=42.14g$