Question

A 14.5 L sample of gas at 1.6 atm and 26.00 C is heated to 97.0 0 C and transferred to a container where its pressure is 1.00 atm. What is the volume of the container?

Answer 1

$\frac {P1V1}{T1}=\frac{P2V2}{T2}$

$V2$ is the volume of container

$V2 = \frac{P1V1T2}{T1P2}$

T1 = 273+26=299K

T2= 273+97=370k

$V2= \frac{1.6×14.5×370}{299×1.00}=28.7L$