What is the number of formula units in 23.8 g of sodium nitrate, NaNO3 ? Show work
Molar Mass of Sodium Nitrate =85g
Numberofmoles=1mole×23.8g85g=0.271molesNumber of moles =\frac {1mole ×23.8g}{85g}=0.271molesNumberofmoles=85g1mole×23.8g=0.271moles
N=0.271×6.02×1023N=0.271 ×6.02 ×10 ^{23}N=0.271×6.02×1023
N=1.631×1023N=1.631×10 ^{23}N=1.631×1023
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