Question #177355

Heat of naturalization using measurements probes


Heat of naturalization of HCl with NaOH:

  1. temperature of calorimeter and NaOH = 23.00 degree celcius
  2. change in temperature (from curve) = 30.00 defree celcius
  3. heat gained by the solution (temperature increase X 10.0g X 4.18 J/L-g) = ?J
  4. heat gained by calorimeter (temperature increase X heat capacity of calorimeter) = ?J
  5. total heat release (#3 + #4) = ?J
  6. balance equation for the reaction = ?J
  7. moles of HCl in 5.0 mL of 1.0M HCl = ?
  8. moles of NaOH in 5.0 mL of 1.0M NaOH = ?
  9. moles of water produced (balanced equation) = ?
  10. KJ released per mole of water formed (#5 / #9) X 10-3 = ?KJ/mol


find number 3, 4, 5, 6, 7, 8, 9, and 10.


1
Expert's answer
2021-04-02T05:11:12-0400

Heat gained by the solution =7×10×4.18=292.67×10×4.18=292.6


Moles of HCL =51000×1=5.0×103=\frac{5}{1000}×1=5.0×10^{-3}


Moles of NaOH =51000×1=5.0×103=\frac{5}{1000}×1=5.0×10^{-3}




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