Answer to Question #177339 in General Chemistry for Cash conner

Question

4 mol NH3 + 5 mol oxygen gas-> 4 mol nitrogen monoxide+ 6 mol water if 172.68 grams of nitrogen monoxide are produced how many grams of water will also be produced

Answer 1

2C₈H₁₈+25O₂-->16CO₂+18H₂O

moles C8H18 used$= 25.1g ×\frac{1 mole}{114 g} = 0.220moles$

Assuming complete combustion, you can now figure out how many moles of CO₂ are produced, since the equation tells you that 2 moles C₈H₁₈ produces 16 moles CO₂.

 

moles CO₂ produced $=0.220 ×16$

moles CO₂/2 moles C₈H₁₈ $=\frac{0.220 ×16}{2}=1.76moles$ of CO₂ are produced