Answer to Question #176779 in General Chemistry for Tia Fountain

Question

The temperature of a 3.50 L sample of gas is lowered from 355K to 225K.  What will be the resulting volume of the gas?

Answer 1

$\frac {V1}{T1}= \frac {V2}{T2}$

The resulting volume of gas will be V2

$V2= \frac {V1T2}{T1}$

$V2 = \frac{3.50×225}{355}=2.22L$