The pressure of a sample of helium in a 1.50-L container is 0.88 atm. What is the new pressure if the sample is placed in a 2.00 L container?
P1V1 = P2V2
0.88 atm × 1.50L = 2.00L × X
1.32 = 2.00X
X = 1.32/2.00
= 0.66 atm
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment