Answer to Question #176158 in General Chemistry for Fraise Smith

Question

A 500-ml aqueous solution initially contained 0.001M HZX. During equilibrium, ZX- ions were measured and the concentration was 5 x 10-13 M. Determine the chemical equilibrium constant expression and the chemical equilibrium constant.

Answer 1

Chemical equilibrium constant expression

H2O + HZX -> H3ZXO

= H3ZXO/ (H2O)(HZX)

Chemical equilibrium constant

= K = H3ZXO/ (H2O)(HZX)

= 1 + 0.001 = (1.001/1×1) × 5×10^-13

K = 5×10^-13