Answer to Question #176074 in General Chemistry for Cole Coffman

Question

If you had 12.00 grams of water at 70.0C, under constant pressure of 1.00 atm, how much energy would be released to cool it to -20.5C

Answer 1

q = m c $\Delta T$

q = heat released

c = specific heat of water = 4.186 j/g⁰C

$\Delta T$ = T₂ - T₁ = -20.5⁰C - 70⁰C = -95⁰C

m = 12 g

q = 12×4.186×(-95)

q = -4772.04 joules

q = 4772.04 joules released