Question

What volume (in Liters) of 1.2 M HCl is needed to contain 15.6 g HCl?

Answer 1

HCL has a molar mass of 36.46 g/mol

which means that the 15.6g

 sample will contain $=(\frac{15.6}{36.46})= 0.428$ moles HCL

Molarity=moles of solute/liters of solution

HCL solution will contain 1.2

moles of hydrochloric acid for every liter of solution. This means that 0.428

moles will come with a volume of

$V= \frac{0.428}{1.2}=0.356L$