What volume (in Liters) of 1.2 M HCl is needed to contain 15.6 g HCl?
HCL has a molar mass of 36.46 g/mol
which means that the 15.6g
sample will contain "=(\\frac{15.6}{36.46})= 0.428" moles HCL
Molarity=moles of solute/liters of solution
HCL solution will contain 1.2
moles of hydrochloric acid for every liter of solution. This means that 0.428
moles will come with a volume of
"V= \\frac{0.428}{1.2}=0.356L"
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