determine the enthalpy change for the reaction:
Zn(s) + Cu2+(aq) → Cu(s) + Zn2+(aq)
q (enthalpy change) = (mass of solution) x (specific heat capacity) x (temperature change)
q = 50g (from the 50cm cubed) x 4.18 x 6.3 = 1316.7 J
also, number of moles = concentration x volume divided by 1000
n = 1.0 x 50 / 1000 = 0.05 moles
so 0.05 moles = 1316.7 J
1 mole = 1316.7 divided by 0.05 = 26334 J and if we divide that by 1000 = 26.334 kJ
or q = - 26.334kJ/mol
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