Answer to Question #171950 in General Chemistry for Paris

Question

Calculate the pKa of a 0.062 M HOCl solution with a pH of 5.84. 

Provide answer to two decimal places and without units.

Answer 1

HOCl = H⁺ + OCl^-

Ka = [H⁺][OCl^-]/[HOCl] = [H⁺]²/(c(HOCl) - [H⁺]) = 10^-2*5.84/(0.062 - 10^-5.84) = 3.37*10^-11

pKa = -log(Ka) = 10.47