Question

If 0.368 g of fuel increases the temperature of a calorimeter by 24.1°C, and the calorimeter is calibrated at 9.28 kJ/°C, calculate the heat

of combustion of fuel per gram. SHOW ALL YOUR WORK.

Answer 1

Given, mass of fuel = 0.368g

Raise in temperature = 24.1

Specific heat = 9.28 kJ/C

$Heat involved = S * \Delta T$

Heat of combustion =$\frac{Heat involved}{mass}$

=607.74 kJ/g