If 0.368 g of fuel increases the temperature of a calorimeter by 24.1°C, and the calorimeter is calibrated at 9.28 kJ/°C, calculate the heat
of combustion of fuel per gram. SHOW ALL YOUR WORK.
Given, mass of fuel = 0.368g
Raise in temperature = 24.1
Specific heat = 9.28 kJ/C
"Heat involved = S * \\Delta T"
Heat of combustion ="\\frac{Heat involved}{mass}"
=607.74 kJ/g
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