A buffer contains equal concentrations of a weak acid HA and its conjugate base A−. If the value of Ka for HA is 1.0 × 10−9 , what is the pH of the buffer?
1. 7.0
2. 1.0
3. 5.0
4. 13.0
5. 9.0
1.0×10−9=[H+][NH3][NH+4]=x(0.0500)
0.0350
5.6×10−10=[H+][NH3][NH4+]=x(0.0500)0.0350
Solving for x (H+):
x = [H+] = 3.92 x 10-10
pH = -log(3.92 x 10-10)
pH = 9.41
= 9
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