What is the pH of an aqueous solution that is 0.011 M HF (Ka = 3.5 × 10−4 ) and 0.015 M NaF?
1. 3.33
2. 3.59
3. 3.46
4. 1.95
5. 5.27
According to Henderson-Hasselbalch equation:
pH=pKa+logC(salt)/C(acid)
pKa=-logKa=-log3.5*10-4=3.456
pH=3.456+log0.015/0.011=3.456+0.135=3.59.
Answer: 2 - 3.59.
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