Answer to Question #170254 in General Chemistry for ALMOND

General Chemistry

Question #170254

A 7 g metal sample absorbed 211 J of heat as it was heated from 28° C to 85° C. What is the specific heat of the metal?

Expert's answer

Q = 211 J

m = 7g

$\Delta T$ = 85⁰C - 28⁰C = 57⁰C

c = specific heat

Q = mc $\Delta T$

211 = 7×c×57

c = 211/(57×7)

c = 0.529 j/g ⁰C

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