Answer to Question #170250 in General Chemistry for ALMOND

Question #170250

A 505 g piece of copper tubing is heated to 99.9 degrees Celsius & placed in an insulated vessel containing 59.8 g of water at 24.8 degrees Celsius. Assuming that no heat is lost to the vessel, what is the final temperature of the system?


1
Expert's answer
2021-03-09T07:46:03-0500

Use the equation;

q =mc"\\Delta"T

According to Law of conservation of energy;

Heat lost by copper tubing = Heat gained by the water

Thus; -(mc"\\Delta"T)Cu = (mc"\\Delta"T)

-(505g)(0.385J/gK)[Tf -(99.9 + 273)K] = (59.8g)(4.184J/gK)[Tf - (24.8+273)K]

(-194.425J/K)Tf + 72501.0825J = (250.2032J/K)Tf - 74510.51J


Putting like terms together;


72501.0825J + 74510.51J = (194.425J/K)Tf + (250.2032J/K)Tf


147011.5925J = (444.6282J/K)Tf


"Tf=\\dfrac{147011.5925J}{444.6282J\/K}"


Tf = (330.64K - 273)0C


= 57.60C

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