Answer to Question #170182 in General Chemistry for Grace Thompson

Question

Assuming an efficiency of 38.30%,

38.30%, calculate the actual yield of magnesium nitrate formed from 114.4 g

114.4 g of magnesium and excess copper(II) nitrate.

Mg+Cu(NO3)2⟶Mg(NO)2+Cu

Answer 1

Mg + Cu(NO₃)₂ = Mg(NO₃)₂ + Cu

Mg = Mg(NO₃)₂

24 g Mg = 148g Mg(NO₃)₂

1g Mg = 148/24 Mg(NO₃)₂

114.4g Mg = 148× 114.4g/ 24 Mg(NO₃)₂

= 705.5g ( This is the theoretical yield)

%efficiency = actual yield/ theorectical yield × 100%

actual yield = % efficiency × theoretical yield/ 100%

= 38.8% ×705.5 /100%

= 270.2g