Answer to Question #169061 in General Chemistry for Zotana

Question #169061

Compare the number of calories absorbed when 359 g of ice at 0°C is changed to liquid water at 38°C with the number of calories absorbed when 359 g of liquid water is warmed from 0°C to 38°C.


1
Expert's answer
2021-03-10T06:04:22-0500

The number of calories absorbed when 359 g of ice at 0°C is changed to liquid water at 38°C:


"Q_1=\\lambda m+c_wm\\Delta t."

The number of calories absorbed when 359 g of liquid water is warmed from 0°C to 38°C:


"Q_2=c_wm\\Delta t."

The difference:


"\\Delta Q=Q_1-Q_2=\\lambda m=80\u00b7359=28720\\text{ cal}."


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