Answer to Question #169055 in General Chemistry for En Hui Peng

Question

What mass of Br₂ is needed to react with 9.7 g of aluminum? Round to two decimal places?

Answer 1

2 Al + Br₂ $\to$ 2 Al Br

no. Of moles of Al = 9.7/26.98 = 0.359 moles

2 moles of Al react with 1 mole of Br₂

0.359 moles of Al react with 0.1795 moles of Br₂

Grams of Br₂ = 0.1795×159.8 = 28.68g