Answer to Question #167163 in General Chemistry for Daya

Question #167163

Please with the steps....

C6H6 (l) + Br2 (l) ------> C6H6Br (l) + HBr (g)

If 54.6 g of benzene is mixed with 132 g of bromine,

How many grams of bromobenzene are formed in the reaction?

Mass=.......g

Expert's answer

54.6/78= 0.7 moles.

132/160=0.825 moles.

0.7 x 157 = 109.9 g of brombenzene

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