An unknown gas at 77.1
∘
C
and 1.05 atm
has a molar mass of 44.10 g/mol.
Assuming ideal behavior, what is the density of the gas?
We have given,
Temperature, T = 77.1∘C77.1^{\circ} C77.1∘C =350.1K350.1K350.1K
Pressure, P = 1.051.051.05 atm
Molar Mass, M=44.10g/molM = 44.10 g/molM=44.10g/mol
Let the density of gas be d
Using the Ideal gas equation,
PV=nRTPV = nRTPV=nRT
1.05×V=m44.10×8.314×350.11.05\times V = \dfrac{m}{44.10}\times 8.314\times 350.11.05×V=44.10m×8.314×350.1
mV=46.3052910.73\dfrac{m}{V} = \dfrac{46.305}{2910.73}Vm=2910.7346.305
d=0.0159g/mold = 0.0159g/mold=0.0159g/mol
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