A gas at 45°c occupies a volume of .50 L. At a volume of 2.75 L, what is the temperature?
Considering the factors involved, it is evident that Charles law should be applied which is represented mathematically as V1/T1 = V2/T2
Where V1= 50L, T1= 45°C= 318K , V2 = 2.75L, T2 = ?
T2 = (V2 x T1)/V1
= (2.75 x 318)/50
= 17.49K
Therefore, the temperature is 17.49K = -255.51°c
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