find the number of molecules of oxygen required to convert 6.60 dm^3 of SO2 measured at s.t.p to SO3
2SO2 + O2 "\\to" 2SO3
6.60dm3=6.6L
n(SO2)=6.6L/22.4L=0.2946mol
n(O2)=0.2946mol/2=0.1473mol
N(O2)=0.1473×6.02×1023 = 0.887×1023
= 8.87 × 1022
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments
Leave a comment