7. Consider the balanced equation : CH 4 (g)+ H 2 O(l) iff CO(g)+3H 2 (g) Initially, the concentration of the CH 4 is 0.200 M. At equilibrium, the concentration of the CO is 0.0500 M. Calculate K eq for this reaction.
[CH4] = 0.2 - 0.05 = 0.15 M
[H2] = 3[CO] = 3"\\times{}"0.05 = 0.15 M
K = "\\frac{[CO\\times[H_2]^3]}{[CH_4]} = \\frac{0.05\\times0.15^3}{0.15} = 1.125\\times10^{-3} (\\frac{mol^3}{l^3})"
Answer: K = 1.125"\\times"10-3 "\\frac{mol^3}{l^3}".
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