Answer to Question #166451 in General Chemistry for Teeeeeeeeeeera

Question

How many grams of aluminum oxide will be formed upon the complete reaction of 31.6 grams of aluminum with excess iron(III) oxide?

Fe2O3 (s) +2Al (s) -------> Al2O3 (s) +2Fe (s)

..............grams aluminum oxide

please with steps

Answer 1

Solution:

n(Al) = 31.6/27 = 1.17 mole

n(Al₂O₃) = 0.585 mole

m(Al₂O₃) = 0.585×102 = 59.7 g