Question

1. How many moles of nitrate ions are present in a sample that contains 5.24 moles of lead(II) nitrate, Pb(NO₃)₂?

.............moles NO3-

2. How many moles of Pb(NO₃)₂ are present in a sample that contains 6.91 moles of nitrate ions?

............moles Pb(NO3)2

Please with steps

Answer 1

1. From the molar equation;

$5.4mol Pb(NO_3)_2\times$ $1mol(NO_3^-)\over1molPb(NO_3)_2$ $=5.4mol NO_3^-$

2. $6.1mol NO_3^-\times$ $2mol Pb(NO_3)_2\over 1mol NO_3^-$ $=12.2 mol Pb(NO_3)_2$