Answer to Question #166214 in General Chemistry for Savannah Oxenreider

Question #166214

A 0.732 kg sample of gold is added to 100.0 mL of water. The density of gold is 19.32 g/mL. What is the final volume of water?



1
Expert's answer
2021-02-24T03:41:24-0500

Mass of gold = 0.732 kg=732 gm

Density of gold=19.32g/ml

Now

"\\Rightarrow" volume of gold ("V_1" ) ="\\dfrac{mass}{density}"


"V_1" = "\\dfrac{732}{19.32}"

"V_1" =37.89 ml


Volume of water given"(V_2)" =100.0 ml

As water and gold do not mix with each otherso according to that the total volume

"\\Rightarrow" "V_1+V_2"

"\\Rightarrow" 37.89"+" 100.0 ml

"\\Rightarrow" 137.89 ml


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