Question

C6H6(l) + Br2(l) ----> C6H5Br(l) + HBr(g)

If 60.5 g of benzene is mixed with 134g of bromine,

How many grams of bromobenzene are formed in the reaction?

Mass=...........g

Please write it with the steps.

Thanks.....

Answer 1

From the chemical equation;

$60.5gC_6H_5\times$ $1mol C_6H_6\over 78.11gC_6H_6$ $\times$ $1mol C_6H_5Br\over 1mol C_6H_6$ $\times$ $157.0gC_6H_5Br\over 1mol C_6H_5Br$ $=121.60gC_6H_5Br$

$134gBr_2\times$ $1mol Br_2\over 159.6gBr_2$ $\times$ $1mol C_6H_5Br\over 1mol Br_2$ $\times$ $157.0gC_6H_5Br\over 1mol C_6H_5Br$ $=131.81gC_6H_5Br$

Mass$=253.41g$