Question

Determine the formula of the oxide Which contains S-50,0%

Answer 1

$50gS=$ $1mol \over 32.066g$ $=1.559mol S$

$50gO=$ $1mol\over 15.99gO$ $=3.12mol O$

Mole ratio$=$ $3.12\over 1.559$ $=1:2$

The compound thus contains $1mole S$ and $2mole O$

$\therefore$ The compound is $SO_2$