Answer to Question #165702 in General Chemistry for Danaya Perlitz

Question

Could 1 mole of peas fit in a 5m x 8m x 2.5m classroom?

Answer 1

If you selected a hundred($10^2$ ) average size paes,you would find they occupy roughly the volume of 20 $cm^3$ .

so according to this :

$\Rightarrow$ 20 $cm^3$ volume is covered by the peas = $10^2$

$\Rightarrow$ 1 $cm^3$ volume covered by =$\dfrac{10^2}{20}$ = 5 Peas.

Now volume of the given room=$5m\times8m\times2.5m=100m^3$ or $10^8 cm^3$

This volume covered peas =$10^8\times5$ Peas only.

but 1 mol of peas contains $6.022\times10^{23}$ peas which is more than our calculated peas that is$5\times10^8$

So we can say tha 1 mol peas can not fit in the given room.