Answer to Question #161000 in General Chemistry for Arvin Shopon

Question

Work: Neutralization titration

Occupational safety:

V (sample) = 10.0 ml = 10.0 ∙ 10−3 dm³

c (NaOH) = 1.0 mol/dm³

Ք (food vinegar) = 1,0 g / ml = 1 000 g / dm³

V (NaOH) =

1. Write the reaction equation for the neutralization reaction between acetic acid and sodium hydroxide (remember the symbols of the state).

 

2. Calculate the amount of sodium hydroxide needed to neutralize the acetic acid in the sample solution.

  

3. Utilize a balanced reaction equation and volume of the sample solution and determine the acetic acid concentration of food vinegar.

 

 4. Determine the mass percentage of acetic acid in food vinegar. You can assume that the density of food vinegar is 1.0 g/ml.

 

5. Compare the result obtained in step 4 with the concentration indicated on the label of the food vinegar bottle.

6. Calculate how many percentage points the result you obtained differed from the value indicated on the label.

 

7. Consider what the potential difference might be. Mention two points.

 

8. How could you get a more accurate result? Mention one point.

Answer 1

1)

(CH3COOH) + (OH-) > (H2O) + (CH3COO-).

2)mass of sodium

$Mass= m oles× rfm$

=1 ×40

=40g

• 3)An acid – base titration is used to determine the unknown concentration of an acid or base by neutralizing it with an acid or base of known concentration.
• Neutralization is the reaction between an acid and a base, producing a salt and a neutralized base.
• A strong acid yields a weak conjugate base (A^–), so a strong acid is also described as an acid whose conjugate base is a much weaker base than water