Calculate the pH of a buffer solution
formed by dissolving 0.0350 mole
HCH3COO and 0.550 mole of NaCH3COO
in 0.950 L solution. Ka of HCH3COO = 1.8 x
-5 10 .
Molar concentration of CH3COOH = (0.035/0 950)=0.036mol/L
Molar concentration of CH3COONa = (0.55/0.950)=0 578mol/L
Pka= -log(Ka)= 4.74
This is an acedic buffer solution
pH= pKa+ log(CH3COONa/CH3COOH)
=5.94
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